14.6.5. Parallel Parametric Study ExampleΒΆ

  1. The source code is shown below, which can be downloaded here.
  2. Run the source code with 2 processors
mpiexec -np 2 python paralleltruss2.py

the outputs look like

Processor 0
Node 4 (E = 3000.0 ) Disp : [0.5300927771322836, -0.17789363846931766]
Processor 1

Node 4 (E = 6000.0 ) Disp : [0.2650463885661418, -0.08894681923465883]


Process 1 Terminating
Process 0 Terminating

The script is shown below

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import openseespy.opensees as ops

pid = ops.getPID()
np = ops.getNP()
ops.start()
if np != 2:
    exit()

ops.model('basic', '-ndm', 2, '-ndf', 2)

if pid == 0:
    E = 3000.0
else:
    E = 6000.0

ops.uniaxialMaterial('Elastic', 1, E)

ops.node(1, 0.0, 0.0)
ops.node(2, 144.0, 0.0)
ops.node(3, 168.0, 0.0)
ops.node(4, 72.0, 96.0)

ops.fix(1, 1, 1)
ops.fix(2, 1, 1)
ops.fix(3, 1, 1)

ops.element('Truss', 1, 1, 4, 10.0, 1)
ops.timeSeries('Linear', 1)
ops.pattern('Plain', 1, 1)
ops.load(4, 100.0, -50.0)

ops.element('Truss', 2, 2, 4, 5.0, 1)
ops.element('Truss', 3, 3, 4, 5.0, 1)

ops.constraints('Transformation')
ops.numberer('ParallelPlain')
ops.system('Umfpack')
ops.test('NormDispIncr', 1e-6, 6)
ops.algorithm('Newton')
ops.integrator('LoadControl', 0.1)
ops.analysis('Static')

ops.analyze(10)


if pid == 0:
    print('Processor 0')
    print('Node 4 (E =', E, ') Disp :', ops.nodeDisp(4))

ops.barrier()

if pid == 1:
    print('Processor 1')
    print('Node 4 (E =', E, ') Disp :', ops.nodeDisp(4))


ops.stop()